Integrand size = 21, antiderivative size = 224 \[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=-\frac {\arctan \left (\sqrt {3}-\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}+\frac {\arctan \left (\sqrt {3}+\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}+\frac {\arctan \left (\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\sqrt {3} \log \left (1-\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b}-\frac {\sqrt {3} \log \left (1+\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b} \]
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Time = 0.21 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2654, 301, 648, 632, 210, 642, 209} \[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=-\frac {\arctan \left (\sqrt {3}-\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}+\frac {\arctan \left (\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\sqrt {3}\right )}{2 b}+\frac {\arctan \left (\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\sqrt {3} \log \left (\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}-\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+1\right )}{4 b}-\frac {\sqrt {3} \log \left (\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}+\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+1\right )}{4 b} \]
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Rule 209
Rule 210
Rule 301
Rule 632
Rule 642
Rule 648
Rule 2654
Rubi steps \begin{align*} \text {integral}& = \frac {3 \text {Subst}\left (\int \frac {x^4}{1+x^6} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b} \\ & = \frac {\text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\text {Subst}\left (\int \frac {-\frac {1}{2}+\frac {\sqrt {3} x}{2}}{1-\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\text {Subst}\left (\int \frac {-\frac {1}{2}-\frac {\sqrt {3} x}{2}}{1+\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b} \\ & = \frac {\arctan \left (\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\text {Subst}\left (\int \frac {1}{1-\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{4 b}+\frac {\text {Subst}\left (\int \frac {1}{1+\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{4 b}+\frac {\sqrt {3} \text {Subst}\left (\int \frac {-\sqrt {3}+2 x}{1-\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{4 b}-\frac {\sqrt {3} \text {Subst}\left (\int \frac {\sqrt {3}+2 x}{1+\sqrt {3} x+x^2} \, dx,x,\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{4 b} \\ & = \frac {\arctan \left (\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\sqrt {3} \log \left (1-\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b}-\frac {\sqrt {3} \log \left (1+\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,-\sqrt {3}+\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}-\frac {\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\sqrt {3}+\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b} \\ & = -\frac {\arctan \left (\sqrt {3}-\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}+\frac {\arctan \left (\sqrt {3}+\frac {2 \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{2 b}+\frac {\arctan \left (\frac {\sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}\right )}{b}+\frac {\sqrt {3} \log \left (1-\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b}-\frac {\sqrt {3} \log \left (1+\frac {\sqrt {3} \sqrt [3]{\sin (a+b x)}}{\sqrt [3]{\cos (a+b x)}}+\frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)}\right )}{4 b} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.03 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.25 \[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=\frac {3 \cos ^2(a+b x)^{5/6} \operatorname {Hypergeometric2F1}\left (\frac {5}{6},\frac {5}{6},\frac {11}{6},\sin ^2(a+b x)\right ) \sin ^{\frac {5}{3}}(a+b x)}{5 b \cos ^{\frac {5}{3}}(a+b x)} \]
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\[\int \frac {\sin ^{\frac {2}{3}}\left (b x +a \right )}{\cos \left (b x +a \right )^{\frac {2}{3}}}d x\]
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Leaf count of result is larger than twice the leaf count of optimal. 390 vs. \(2 (178) = 356\).
Time = 0.34 (sec) , antiderivative size = 390, normalized size of antiderivative = 1.74 \[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=-\frac {\sqrt {\frac {1}{2}} b \sqrt {\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} + 1}{b^{2}}} \log \left (-\frac {2 \, {\left (\sqrt {\frac {1}{2}} b \sqrt {\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} + 1}{b^{2}}} \sin \left (b x + a\right ) + \cos \left (b x + a\right )^{\frac {1}{3}} \sin \left (b x + a\right )^{\frac {2}{3}}\right )}}{\sin \left (b x + a\right )}\right ) - \sqrt {\frac {1}{2}} b \sqrt {\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} + 1}{b^{2}}} \log \left (\frac {2 \, {\left (\sqrt {\frac {1}{2}} b \sqrt {\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} + 1}{b^{2}}} \sin \left (b x + a\right ) - \cos \left (b x + a\right )^{\frac {1}{3}} \sin \left (b x + a\right )^{\frac {2}{3}}\right )}}{\sin \left (b x + a\right )}\right ) + \sqrt {\frac {1}{2}} b \sqrt {-\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} - 1}{b^{2}}} \log \left (-\frac {2 \, {\left (\sqrt {\frac {1}{2}} b \sqrt {-\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} - 1}{b^{2}}} \sin \left (b x + a\right ) + \cos \left (b x + a\right )^{\frac {1}{3}} \sin \left (b x + a\right )^{\frac {2}{3}}\right )}}{\sin \left (b x + a\right )}\right ) - \sqrt {\frac {1}{2}} b \sqrt {-\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} - 1}{b^{2}}} \log \left (\frac {2 \, {\left (\sqrt {\frac {1}{2}} b \sqrt {-\frac {\sqrt {3} b^{2} \sqrt {-\frac {1}{b^{4}}} - 1}{b^{2}}} \sin \left (b x + a\right ) - \cos \left (b x + a\right )^{\frac {1}{3}} \sin \left (b x + a\right )^{\frac {2}{3}}\right )}}{\sin \left (b x + a\right )}\right ) + 2 \, \arctan \left (\frac {\cos \left (b x + a\right )^{\frac {1}{3}}}{\sin \left (b x + a\right )^{\frac {1}{3}}}\right )}{2 \, b} \]
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\[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=\int \frac {\sin ^{\frac {2}{3}}{\left (a + b x \right )}}{\cos ^{\frac {2}{3}}{\left (a + b x \right )}}\, dx \]
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\[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=\int { \frac {\sin \left (b x + a\right )^{\frac {2}{3}}}{\cos \left (b x + a\right )^{\frac {2}{3}}} \,d x } \]
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\[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=\int { \frac {\sin \left (b x + a\right )^{\frac {2}{3}}}{\cos \left (b x + a\right )^{\frac {2}{3}}} \,d x } \]
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Time = 0.83 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.20 \[ \int \frac {\sin ^{\frac {2}{3}}(a+b x)}{\cos ^{\frac {2}{3}}(a+b x)} \, dx=-\frac {3\,{\cos \left (a+b\,x\right )}^{1/3}\,{\sin \left (a+b\,x\right )}^{5/3}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{6},\frac {1}{6};\ \frac {7}{6};\ {\cos \left (a+b\,x\right )}^2\right )}{b\,{\left ({\sin \left (a+b\,x\right )}^2\right )}^{5/6}} \]
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